4x^2+42x-46=0

Solution for 4x^2+42x-46=0 equation:

4x^2+42x-46=0

a = 4; b = 42; c = -46;
Δ = b2-4ac
Δ = 422-4·4·(-46)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-50}{2*4}=\frac{-92}{8}
=-11+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+50}{2*4}=\frac{8}{8}
=1
$